95x-(2500+10x+0.2x^2)=0

Solution for 95x-(2500+10x+0.2x^2)=0 equation:

95x-(2500+10x+0.2x^2)=0

We get rid of parentheses

-0.2x^2-10x+95x-2500=0

We add all the numbers together, and all the variables

-0.2x^2+85x-2500=0

a = -0.2; b = 85; c = -2500;
Δ = b2-4ac
Δ = 852-4·(-0.2)·(-2500)
Δ = 5225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5225}=\sqrt{25*209}=\sqrt{25}*\sqrt{209}=5\sqrt{209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-5\sqrt{209}}{2*-0.2}=\frac{-85-5\sqrt{209}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+5\sqrt{209}}{2*-0.2}=\frac{-85+5\sqrt{209}}{-0.4}
$